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Q) Prove that: 1 + = cosec α (Q 22 B – 30/2/2 – CBSE 2026 Question Paper) Ans: Let’s start from LHS: LHS = 1 + Step 1: From Trigonometric identities, we know that 1 + cot 2 α = cosec 2 α ∴ cot 2 α = cosec 2 α – 1 Step 2: Let’s substitute the value of cot 2 […]
22 b. Prove that: 1 + (cot^2 α)/(1 + cosec α) = cosec α Read More »
Q) Evaluate: (Q 22 A – 30/2/2 – CBSE 2026 Question Paper) Ans:Â Let’s solve numerator and denominator one by one and then combine: Step 1: Solving for numerator: (5 cos 2Â 60Â 0 + 4 sec 2Â 30Â 0 – tan 2Â 45Â 0) = 5 Â Â Â Â (by putting values) = 5 = = Step 2: Solving for
22 a. Evaluate: (5cos^2 60 + 4 sec ^ 2 30 – tan ^2 45) / (sin^2 30 + cos^2 30) Read More »
Q) In the given figure, O is the centre of the circle. PQ and PR are tangents. Show that the quadrilateral PQOR is cyclic. (Q 23 – 30/2/2 – CBSE 2026 Question Paper) Ans: Since in a cyclic Quadrilateral, sum of opposite angles is 180 0 ∴ if we need to prove that PQOR is a
Q) Find the value of p, for which one zero of the quadratic polynomial p x 2 – 14 x + 8 is 6 times the other. (Q 24 – 30/2/2 – CBSE 2026 Question Paper) Ans: Step 1: Let the roots be α and β. It is given that one zero is 6 times the
Q)Â If the points A(4, 5) B(m, 6) C(4,3) and D(1, n) taken in this order are the vertices of a parallelogram ABCD, then find the values of m and n. (Q 25 – 30/2/2 – CBSE 2026 Question Paper) Ans:Â We know that the in a parallelogram, the diagonals bisect each other. It means
Q) Prove that: = sec θ . cosec θ (sec θ + cosec θ) (Q 26 A – 30/2/2 – CBSE 2026 Question Paper) Ans: Step 1: Let’s start from LHS: = = = = Step 2: Since sin 2 θ + cos 2 θ = 1 ∴ 1 – cos 2 θ = sin
Q) If = p and = q, then prove that (p 2– q 2) sec 2 α = p 2 (Q 26 B – 30/2/2 – CBSE 2026 Question Paper) Ans: Step 1: Given that: = p  and  = q With the help of given values, first let’s develop the given equation to prove: (p
Q) Find the area of the segment AYB shown in the figure, if the radius of the circle is 21 cm and angle AOB = 1200. [Use Ï€ = 22/7] (Q 27 – 30/2/2 – CBSE 2026 Question Paper) Ans: Step 1: From the diagram, we can see that the area of segment AYB =
Q) Two dice are thrown at the same time. Determine the probability that:(i)Â Â the sum of the numbers on the two dice is 5.(ii)Â the difference of the numbers on the two dice is 3. (Q 28 – 30/2/2 – CBSE 2026 Question Paper) Ans: We know that in case of n dice, the total
Q)Â Find the coordinates of the points of trisection of the line segment joining the points A(- 1, 4) and B(- 3, – 2) (Q 30 – 30/2/2 – CBSE 2026 Question Paper) Ans:Â Step 1: Since, A Trisection means dividing a line segment into three equal parts. It means, if AB is a line,