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Q) The ratio of the 11th term to 17th term of an A.P. is 3:4. Find the ratio of 5th term to 21st term of the same A.P. Also, find the ratio of the sum of first 5 terms to that of first 21 terms.

Ans:

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STEP BY STEP SOLUTION

We know that nth term of an A.P.  =  a + (n-1) d

Therefore,  11th term, N11 = a + 10d and 17th term, N17 = a + 16d

Given that : The ratio of the 11th term = The ratio of the 11th term

The ratio of the 11th term    The ratio of the 11th term = The ratio of the 11th term

or 4a + 40 d = 3a + 48 d

or a = 8d ……………………………………. equation no. (i)

Now 5th term N5 = a + 4d and 21st term N21 = a + 20 d

Therefore,  The ratio of the 11th term = The ratio of the 11th term

Substituting a = 8d from equation (i), we get

The ratio of the 11th term   = The ratio of the 11th term = The ratio of the 11th term

Therefore, N5:N21 = 3:7

Let’s calculate ratio of the sum of first 5 terms to that of first 21 terms.

We know that sum of n terms of an A.P.  Sn = The ratio of the 11th term (2a + (n-1) d)

Sum of first 5 terms, S5 = The ratio of the 11th term(2a + 4d)

and Sum of first 21 terms, S21 =    The ratio of the 11th term (2a + 20d)

Therefore, The ratio of the 11th term = The ratio of the 11th term

= The ratio of the 11th term

Substituting a = 8d from equation (i), we get

= The ratio of the 11th term

= The ratio of the 11th term

= The ratio of the 11th term

Therefore, S5 : S21 = 25 : 189

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