Q) Find X in terms of a b, and c: , X ≠ a, b, c Ans: Given equation is: ∴ ∴ [a (X – b) + b (X – a)] (X – c) = 2 c (X – a) (X – b) ∴ (a X – a b + […]
Find x in terms of a b, and c: a/(x – a) + b/(x – b) = 2 c/(x – c), x ≠ a, b, c Read More »
Q) Find X in terms of a b, and c: , X ≠ a, b, c Ans: Given equation is: ∴ ∴ [a (X – b) + b (X – a)] (X – c) = 2 c (X – a) (X – b) ∴ (a X – a b + […]
Find x in terms of a b, and c: a/(x – a) + b/(x – b) = 2 c/(x – c), x ≠ a, b, c Read More »
(Q) The age of a man is twice the square of the age of his son. Eight years hence, the age of the man will be 4 years more than three times the age of his son. Find their present ages. Ans: Let’s consider the present age of Father is X and present age of
Q) Find the value of ‘k’ for which the quadratic equation (k + 1) y2 – 6 (k + 1) y + 3 (k + 9) = 0, k ≠ – 1 has real and equal roots. [CBSE 2024 – Series 5 – Set 1] Ans: Given quadratic equation is: (k
Find the value of k for which the quadratic equation (k + 1) y2 – 6(k +1) y + 3(k +9)= 0 Read More »
Q) A test consists of ‘True’ or ‘False’ questions. One mark is awarded for every correct answer while 1/4 mark is deducted for every wrong answer. A student knew answers to some of the questions. Rest of the questions he attempted by guessing. He answered 120 questions and got 90 marks. 1. If answer to
Q) An asana is a body posture, originally and still a general term for a sitting meditation pose, and later extended in hatha yoga and modern yoga as exercise, to any type of pose or position, adding reclining, standing, inverted, twisting, and balancing poses. In the figure, one can observe that poses can be related
Q) A parabolic arch is an arch in the shape of a parabola. In structures, their curve represents an efficient method of load, and so can be found in bridges and in architecture in a variety of forms. 1. In the standard form of quadratic polynomial, a x2 + b x + c, a, b
Q. Divide the polynomial x3 – 3 x2 + 5 x – 3 by x2 – 2 Ans: To divide the given polynomial, we can write the function as: = = = = = = = = = = = = Therefore, When we divide X3 – 3 X2 + 5 X – 3 by X2
Divide the polynomial x³ – 3x² + 5x – 3 by x² – 2 Read More »
Q. Solve the quadratic equation: 2 X^2 – 7 X + 3 = 0 Ans: Given equation is: 2 X ^2 – 7 X + 3 = 0 ∴ 2 X ^2 – 6 X – X + 3 = 0 ∴ 2 X (X – 3) – 1 (X – 3) = 0 ∴
Q) Find the value of ‘k’ for which the quadratic equation (k + 1) x 2 – 2 (3 k + 1) x + (8 k + 1) = 0 has real and equal roots. [CBSE 2024 – Series 4 – Set 2] Ans: Given quadratic equation is: (k + 1) x
Q) Find the zeroes of the polynomial 4×2 + 4x – 3 and verify the relationship between zeroes and coefficients of the polynomial. Ans: In the given polynomial equation, to find zeroes, we will start with f(x) = 0 Therefore, 4 x2 + 4 x – 3 = 0 Step 1: Let’s start calculating the