Q) Find the area of the minor and the major sectors of a circle with radius 6 cm, if the angle subtended by the minor arc at the centre is 60 deg (Use pi = 3.14 )
Ans: Let’s draw the diagram for better understanding:Â 
Here, we are given that θ = 600, r = 6 cm
âľ â AOB is 600Â Â
Step 1: Area of minor segment:
From the above diagram, Area of minor segment APB
= Area of sector AOBPÂ
We know that Area of sector of a circle = ![]()
Here, we are given that θ = 600, r = 6 cm
â´ Area of sector AOBP = ![]()
=
(3.14) (36) = Â 18.84 cm2
Therefore, the area of minor segment is 18.84 cm2
Step 2: Area of major segment:
From the above diagram, Area of major segment AQB
= Area of the circle – Area of minor segment APB
= Ď (6)2 – 18.84 = 3.14 x 36 – 18.84
= 113.04 – 18.84 = 94.20 cm2
Therefore, the area of major segment is 94.20 cm2
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