Q) Evaluate : (cos 450 + sin 600) / (sec 300+ cosec 300).

We know that: cos 450 = $\frac{1}{\sqrt 2}$; sin 600 = $\frac{\sqrt 3}{2}$; sec 300 = $\frac{2}{\sqrt 3}$; cosec 300 = 2 By submitting these values in the given expression, we get: (cos 450 + sin 600) / (sec 300+ cosec 300) = $\frac{(\frac{1}{\sqrt 2} + \frac{\sqrt 3}{2})}{(\frac{2}{\sqrt 3} + 2)}$ = $\frac{(\frac{2 + \sqrt 6}{2\sqrt 2})}{(\frac{2 + 2 \sqrt 3}{\sqrt 3})}$ = $\frac{(\sqrt 3)(2 + \sqrt 6)}{(2\sqrt 2)(2 + 2 \sqrt 3)}$ = $\frac{(2 \sqrt 3 + \sqrt 18)}{(4\sqrt 2 + 4 \sqrt 6)}$ = $\frac{(2 \sqrt 3 + 3\sqrt 2)}{(4\sqrt 2 + 4 \sqrt 6)}$ Please do press “Heart” button if you liked the solution.