Q. Solve the quadratic equation: 2 X^2 – 7 X + 3 = 0

Ans: Given equation is:

2 X ^2 – 7 X + 3 = 0

∴ 2 X ^2 – 6 X – X + 3 = 0

∴ 2 X (X – 3) – 1 (X – 3) = 0

∴ (X – 3) (2 X – 1) = 0

∴ X = 3 and X =

Therefore values of X are 3 and

Check: Let’s check our answers:

at X = 3 in LHS, equation will become: 2 (3)² – 7 (3) + 3 

= 18 – 21 + 3 = 0

at X = 1/2 in LHS, equation will become: 2 ()² – 7 () + 3 

= 2 – 7 + 3

= – + 3 = – = 0

Since values of LHS matches with given value on RHS, our both answers are correct. 

Please press “Heart” button if you like the solution.