Q) Find the area of the segment AYB shown in the figure, if the radius of the circle is 21 cm and angle AOB = 1200. [Use π = 22/7] (Q 27 – 30/2/2 – CBSE 2026 Question Paper) Ans: Step 1: From the diagram, we can see that the area of segment AYB = […]

Q) Find the area of the segment AYB shown in the figure, if the radius of the circle is 21 cm and angle AOB = 1200. (Q 27 - 30/2/2 - CBSE 2026 Question Paper) Ans: Step 1: From the diagram, we can see that the area of segment AYB = Area of Sector AOBY - Area of Triangle AOB Step 2: Area of Sector AOBY = $(\frac{\theta}{360^\circ})$ π r 2 = $(\frac{120^\circ}{360^\circ}) (\frac{22}{7})$ (21) 2 = $(\frac{1}{3}) (\frac{22}{7})$ x 21 x 21 = 22 x 21 = 462 cm2 Step 3: Area of Triangle = $\frac{1}{2}$ x OA x OB x sin 1200 = $\frac{1}{2}$ x 21 x 21 x $\frac{\sqrt{3}}{2}$ = $\frac{441}{4} \sqrt{3} \approx$ 190.74 cm2 Step 4: Now, Area of Segment AYB = Area of Sector AOBY - Area of Triangle AOB = 462 - 190.74 = 271.26 cm2 Therefore, the area of Segment AYB is approx. 271.26 cm2 Please press ...