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Q) If tan θ =24/7, then find the value of sin θ + cos θ.

(Q 22 A – 30/1/3 – CBSE 2026 Question Paper)

Ans: 

Step 1: We know that in a right angled triangle, tan θ is given by:

\tan \theta = \frac{Opposite~side}{Adjacent~side}

Since we are given that tan θ = \frac{24}{7}

∴ We can assume that Opposite side = 24 k and adjacent side = 7 k 

here, k is a positive integer

Step 2: Now, by pythagorus theorem,

(Hypotenuse) 2 = (Opposite side) 2 + (Adjacent side) 2 

∴ (Hypotenuse) 2 = (24 k) 2 + (7 k) 2 = (576 k 2 + 49 k 2 ) = ( 625 k 2 )

∴  Hypotenuse = √( 625 k 2) = 25 k

Step 3: Value of sin θ = \frac{Opposite~side}{Hypotenuse}

= \frac{24 k}{25 k} = \frac{24}{25}

Similarly, Value of cos θ = \frac{Adjacent~side}{Hypotenuse}

= \frac{7 k}{25 k} = \frac{7}{25}

Step 4: Now, we need to calculate the value of sin θ + cos θ

By substituting the values of sin θ and cos θ from step 3, we get:

sin θ + cos θ = \frac{24}{25} + \frac{7}{25} = \frac{31}{25}

Therefore, value of (sin θ + cos θ) is \frac{31}{25}.

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