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Q) A solid is in the form of a cylinder with hemispherical ends. The total height of the solid is 20 cm and the diameter of the cylinder is 7 cm. Find the total volume of the solid. (Use π = 22/7)

[Q 30 – 30/1/1 – CBSE 2026 Question Paper]

Ans:

Step 1: Let’s make  diagram for our better understanding of the question:

A solid is in the form of a cylinder with hemispherical ends. The total height of the solid is 20 cm and the diameter of the cylinder is 7 cm. Find the total volume of the solid.

Step 2: Here, we can see that the spherical ends are joined with the cylinder and have similar width.

∵ Diameter of the cylinder = 7 cm

∴ Diameter of the spherical ends = 7 cm

∴ Radius of the spherical ends = \frac{7}{2} cm

Step 3: Given that the total height of the object = 20 cm

Height if the cylindrical part = Total height – 2 x radius of a hemispherical end

(There object has 2 spherical end, one each on left and right side)

= 20 – 2 x 3.5 = 20 – 7 = 13 cm

Step 4: Next, the Volume of the solid = Volume of the cylinder + 2 x Volume of the hemispherical ends

= π r 2 h + 2 x \frac{2}{3} π r = π r 2 (h + \frac{4}{3} r)

= (\frac{22}{7}) (\frac{7}{2})^2 [13 + (\frac{4}{3})(\frac{7}{2}] = (\frac{77}{2}) [13 + (\frac{14}{3})]

= (\frac{77}{2}) (\frac{53}{3}) = (\frac{4081}{6}) cm³

Therefore, Volume of the capsule is 680.167 cm3 

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