Q) A box containing cards numbered between 0 and 100 are shuffled and a card is picked at random. Find the probability of getting a card which is:
(a) divisible by 6.
(b) not divisible by 6

ICSE Specimen Question Paper – 2026

(a) Step 1: Let’s start by looking at all possible outcomes:
Since the cards have integers from 0 to 100, the total number of possible outcomes are: N = 101

Step 2: Next, we find total number of favorable outcomes:
Given that we need to identify the multiples of 6 within the range of 0 to 100.
Here possible favorable outcomes are 0, 6, 12 …… 96
Hence, there 17 favorable outcomes

Step 3: Next, we calculate probability of event A (getting a card divisible by 6):
P(A) = favorable outcomes / Total outcomes
= 17/101

(b) Step 4: Cards which have the number not divisible by 6, are 101 – 17 = 84
Hence, we calculate probability of event B (not getting a card divisible by 6):
P(B) = favorable outcomes / Total outcomes
= 84/101

[Alternatively, we apply complement rule i.e. P(B) = 1 – P(A)
= 1 – 17/101 = 84/101]

Therefore, a) The probability of getting a card which is divisible by 6 is 17/101.
(b) The probability of getting a card which is not divisible by 6 is 84/101

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