**Q) A takes twice as much time as B or thrice as much time as C to finish a piece of work. Working together, they can finish the work in 2 days. B can do the work alone in:**

**a) 4 days b) 6 days c) 8 days d) 12 days
**

**Ans:**

Given that the time taken by A = 2 x time taken by B = 3 x time taken by C

In equation terms, we can write it as: A = 2 B = 3 C

∴ in terms of B, A = 2 B and C = 2 B /3

Work done together = 1/A + 1/B + 1/ C

= 1 /(2B) + 1/B + 1/(2 B /3) = 1/2B + 1/B + 3/2B = 6/2B = 3/B

Given that, 3/B = 1/2

∴ B = 6 days

**Hence, Answer is [B].**

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