Q) In Δ ABC, if AD ⊥ BC and AD2 = BD x DC, then prove that ∠BAC = 900 Ans: Since AD ⊥ BC, ∴ ∠ ADB = ∠ ADC = 900 By Pythagoras theorem in Δ ADB, we get: AD2 + BD2 = AB2 ……………. (i) Similarly in Δ ADC, by Pythagoras theorem, […]
In Δ ABC, if AD ⊥ BC and AD2 = BD x DC, then prove that ∠BAC = 90° Read More »
