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Q) If \frac{\sec \alpha }{\cos ec \beta} = p and \frac{\tan \alpha }{\cos ec \beta}= q, then prove that (p 2– q 2) sec 2 α = p 2

(Q 26 B – 30/2/2 – CBSE 2026 Question Paper)

Ans: 

Step 1: Given that:

\frac{\sec \alpha }{\cos ec \beta} = p   and   \frac{\tan \alpha }{\cos ec \beta}= q

With the help of given values, first let’s develop the given equation to prove:

(p 2– q 2) sec 2 α = p 2

[(\frac{\sec \alpha }{\cos ec \beta})^2 - (\frac{\tan \alpha }{\cos ec \beta})^2] . sec 2 α = (\frac{\sec \alpha }{\cos ec \beta})^2

Step 2: Let’s start from LHS:

[(\frac{\sec \alpha }{\cos ec \beta})^2 - (\frac{\tan \alpha }{\cos ec \beta})^2] . sec 2 α

= [(\frac{\sec ^2 \alpha }{\cos ec ^2 \beta}) - (\frac{\tan ^2 \alpha }{\cos ec ^2 \beta})] . sec 2 α

= (\frac{(\sec ^2 \alpha - \tan ^2 \alpha )}{\cos ec ^2 \beta}) . sec 2 α

Step 3: Since 1 + tan 2 θ  = sec 2 θ

∴ sec 2 θ  – tan 2 θ  = 1

and ∴ sec 2 α  – tan 2 α  = 1

Step 4: By substituting this value in LHS, we get:

LHS = (\frac{(\sec ^2 \alpha  - \tan ^2 \alpha )}{\cos ec ^2 \beta}) . sec 2 α

= (\frac{1}{\cos ec ^2 \beta}) . sec 2 α

= \frac{\sec ^2 \alpha }{\cos ec ^2 \beta}

= (\frac{\sec \alpha }{\cos ec \beta})^2 = RHS

Hence Proved!

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