In △ABC, DE ∥ BC. If AD = x, DB = x − 2, AE = x + 2 and EC

Q) In △ABC, DE ∥ BC. If AD = x, DB = x − 2, AE = x + 2 and EC = x − 1, then find the value of x.

(Q 25 A – 30/1/3 – CBSE 2026 Question Paper)

Ans:

Step 1: Let’s make a diagram for better understanding of the question:

Step 2: Since it is given that DE || BC, then by BPT theroem,

$\frac{AD}{DB} = \frac{AE}{EC}$

Step 3: By substituting given values in diagram,

$\frac{\times}{\times - 2} = \frac{\times + 2}{\times - 1}$

∴ X (X – 1) = (X + 2) (X – 2)

∴ X² – X = X² – 4

∴ X = 4

Therefore, the value of X is 4 cm.

Please press the “Heart” button if you like the solution.

Contact us