🚀 Download 21 Must‑Solve Questions for Class 10 Boards!
Chat with us WhatsApp

Q) In the given figure, CM and RN are respectively the medians of △ABC and △PQR.

In the given figure, CM and RN are respectively the medians of △ABC and △P QR. If △ABC ∼ △P QR, then prove that: (i) △AMC ∼ △P NR (ii) △CMB ∼ △RNQ

If △ABC ∼ △PQR, then prove that: (i) Δ AMC ∼ Δ PNR  (ii) Δ CMB ∼ Δ RNQ.

(Q32 B – 30/1/3 – CBSE 2026 Question Paper)

Ans: It is given that:

  1. CM is median of Δ ABC
  2. RN is median of Δ PQR
  3. Δ ABC ∼ Δ PQR

(i) Δ AMC ∼ Δ PNR:

Step 1:  ∵ CM is the median  ∴  AB = 2 AM

Similarly, ∵ RN is the median  ∴  PQ = 2 PN

Step 2: Since Δ ABC ∼ Δ PQR In the given figure, CM and RN are respectively the medians of △ABC and △P QR. If △ABC ∼ △P QR, then prove that: (i) △AMC ∼ △P NR (ii) △CMB ∼ △RNQ

\frac{AB}{PQ} = \frac{AC}{PR}

\frac{2AM}{2PN} = \frac{AC}{PR}

\frac{AM}{PN} = \frac{AC}{PR}

∴ Δ AMC ∼ Δ PNR ….. Hence proved !

(ii) Δ CMB ∼ Δ RNQ:

Step 3:  ∵ CM is the median  ∴  AB = 2 BM

Similarly, ∵ RN is the median  ∴  PQ = 2 QN

Step 4: Since Δ ABC ∼ Δ PQR In the given figure, CM and RN are respectively the medians of △ABC and △P QR. If △ABC ∼ △P QR, then prove that: (i) △AMC ∼ △P NR (ii) △CMB ∼ △RNQ

\frac{AB}{PQ} = \frac{BC}{QR}

\frac{2BM}{2QN} = \frac{BC}{QR}

\frac{BM}{QN} = \frac{BC}{QR}

∴ Δ CMB ∼ Δ RNQ: ….. Hence proved !

Please press the “Heart” button if you like the solution.

Leave a Comment

Your email address will not be published. Required fields are marked *

Scroll to Top