Q) Prove that: ![]()
(Q 30 – 30/4/2 – CBSE 2026 Question Paper)
Ans:
[Note: solved in two methods: please choose whichever you find easier]
Method 1:
Step 1: Let’s start from LHS and simplify it:
LHS = ![]()
= ![]()
= ![]()
= ![]()
= ![]()
= ![]()
∵ by trigonometric identity, sin 2 θ + cos 2 θ = 1
∴ LHS = ![]()
∴ LHS = ![]()
∴ LHS = ![]()
∴ LHS = ![]()
∴ LHS = ![]()
∴ LHS = ![]()
∴ LHS = ![]()
∴ LHS = tan x
Step 2: Let’s take RHS & simplify it:
RHS = ![]()
= ![]()
= ![]()
= ![]()
= ![]()
= ![]()
∵ by trigonometric identity, sin 2 θ + cos 2 θ = 1
∴ RHS = ![]()
∴ RHS = ![]()
∴ RHS = ![]()
∴ RHS = ![]()
∴ RHS = ![]()
∴ RHS = ![]()
∴ RHS = ![]()
∴ RHS = tan x
Since LHS = RHS…….. Hence proved!
Method 2:
Given expression is: ![]()
Step 3:
We can rearrange the given terms to make it simpler:
∴ ![]()
∴
Now, this is simpler form of given experession and we will try to prove if ts LHS is equal to RHS
Step 4: Let’s start from LHS:
LHS = ![]()
= ![]()
= ![]()
= ![]()
= ![]()
Step 5: ∵ by trigonometric identity: 1 + tan 2 θ = sec 2 θ
∴ sec 2 θ – tan 2 θ = 1
By substituting this value in our LHS expression, we get:
∴ LHS = ![]()
= 2 sec x = RHS (of derived expresion in step 3)
Hence Proved !
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