**Q) **Prove that 3√2 is an irrational number.

**Ans: **Let us assume that 3√2 is a rational number

Then we can represent 3√2 as ; where q ≠ 0 and let p, q are co-primes.

3√2 = ………………. (i)

or it can be rearranged as √2 =

Since, 3, a and b are integers,

is a rational number.

Hence, √2 is rational.

But it contradicts the fact that √2 is a irrational number;

**Therefore, 3√2 is an irrational number****………… Hence Proved !**