Prove that 5-2√3 is an irrational number. It is given that

Q) Prove that 5-2√3 is an irrational number. It is given that √3 is an irrational number.

Ans:

Let’s start by considering 5 – 2 √3 is a rational number.

∴ 5 – 2 √3 = $Prove that 5-2√3 is an irrational$ (here p and q are integers and q ≠ 0)

∴ – 2 √3 = $Prove that 5-2√3 is an irrational$ – 5 = $Prove that 5-2√3 is an irrational$

∴ √3 = $Prove that 5-2√3 is an irrational$

Since p and q are integers, so, $Prove that 5-2√3 is an irrational$ is a rational number.

If RHS is a rational number, then LHS will also be a rational

Therefore √3 is a rational number.

But it contradicts the given condition (given that √3 is an irrational number)

Therefore, it is confirmed that 5 – 2 √3 is an irrational number.

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