Q) Solve the quadratic equation 2x2 – 3x – 5 = 0 using the quadratic formula.

Ans: [Approach: we know that the in a quadratic formula, the value of x is calculated by: x = \frac{- b \pm \sqrt{b^2 - 4 a c}}{2 a}, where, b2 – 4 a c is the discriminant. Hence, if we calculate the value of the discriminant and solve by the above formula, we can get value of x]

Given Quadratic equation is: 2 x2 – 3 x – 5 = 0

Step 1: We know that the standard quadratic equation is given by:

a x2 + b x + c = 0

By comparing the given quadratic equation with the standard quadratic equation, we get:

a = 2, b = – 3, c = -5

Step 2: Let’s calculate the discriminant now:

D = b2 – 4 a c = (- 3) – 4 (2) (-5)

= 9 + 40 = 49

Step 3: Let’s solve for x by putting values in the quadratic formula:

x = \frac{- (- 3) \pm \sqrt{49}}{2(2)}

x = \frac{3 \pm 7}{4}

Step 4: Since the discriminant is positive, we get two real roots:

Therefore, x = \frac{3 + 7}{4} = \frac{10}{4} = \frac{5}{2}

and x = \frac{3 - 7}{4} = \frac{- 4}{4} = – 1

Therefore, the solutions of given quadratic equation are: x = \frac{5}{2} and  x = – 1

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