**Q) A person standing on the bank of a river observes that the angle of elevation of the top of a tower on the opposite bank is 60°. When he moves 30 m away from the bank, he finds the angle of elevation to be 30°. Find the height of the tower and width of the river. (Take √3 = 1.732)**

**Ans: **Let’s start with the diagram for this question:

Here, AB is the tower of height H and AC be the river of width D m.

**Step 1: **Let’s start from Δ ABC, tan C = tan 60° =

∴ √3 =

∴ H = D√3 ……………. (i)

**Step 2: **Next, we take Δ ABD, tan 30 =

∴

∴ 30 + D = H √3 …… (ii)

**Step 3:** By solving equations (i) and (ii), we get:

∴ 30 + D = (D √3) √3

∴ 30 + D = 3 D

∴ 30 = 2 D

∴ **D = 15 m**

**Step 4: **

From equation (i), we have H = D √3

∴ H = 15 √3 = 15 x 1.732

∴ **H = 25.98 m**

**Therefore, height of the tower is 25.98 m and width of the river is 15 m.**

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