**Q) **The angle of elevation of the top of a tower 30 m high from the foot of another tower in the same plane is 60^{0} and the angle of elevation of the top of the second tower from the foot of the first tower is 30^{0}. Find the distance between the two towers and also the height of the other tower.

**Ans: **

Let AB and PQ be the towers, heights be 30 m & H m; distance between 2 towers be D m, and angle of elevations be as shown in the image above.

In Δ ABQ,

**or D = 10√3 m**

Now in Δ PQB,

H =

**or H = 10 m**

**Therefore, the distance between the two towers is 10√3 m**** and the height of the other tower is 10 m.**