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Q) Two different coins are tossed simultaneously. What is the probability of getting:
(i) at least one head? (ii) at most one tail ? (iii) a head and a tail?

(Q 29 – 30/1/3 – CBSE 2026 Question Paper)

Ans:

Step 1: We know that in case of n coins, the total outcomes = (2)n

∵ here we have 2 coins, ∴ total outcomes = (2)2 = 4 outcomes

Possible outcomes: {TT, HT, TH, HH}

(i) Probability of at least one head: 

Step 2: At least one head means, toss can have 1 head or 2 heads. Here, 0 head is not OK.

∴ the favorable outcomes: {HT, TH,HH} i.e. 3 outcomes

Step 3: We know that the Probability is given by: \frac{Favourable~outcomes}{Total~outcomes}

Probability to get at least one head, PH = \frac{3}{4}

Therefore, the probability to get at least one head = \frac{3}{4}

(ii) Probability to get at most one tail: 

Step 4: At most one tail means, toss can have 0 tail, or 1 tail. Here, 2 tails are not OK.

∴ the favorable outcomes: {HH, HT, TH} i.e. 3 outcomes

Step 5: ∵ Probability is given by: \frac{Favourable~outcomes}{Total~outcomes}

∴ Probability to get at most one tail, PT = \frac{3}{4}

Therefore, the probability to get at most one tail = \frac{3}{4}

(iii) Probability to get a head and a tail:

Step 6: A Head and a tail means, toss will have one head and one tail together. Here, 2 tails and 2 heads are not OK.

∴ the favorable outcomes: {HT, TH} i.e. 2 outcomes

Step 7: ∵ Probability is given by: \frac{Favourable~outcomes}{Total~outcomes}

Probability to get one head and one tail, PHT = \frac{2}{4} = \frac{1}{2}

Therefore, the probability to get a head and a tail = \frac{1}{2}

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