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Q) In what ratio does the X-axis divide the line segment joining the points(2, – 3) and (5, 6)? Also, find the coordinates of the point of intersection.

Ans: Let’s draw the diagram to solve:

In what ratio does the X-axis divide the line segment joining the points(2, –3) and (5, 6)?

(i) Ratio of division:

We know that the value of y-coordinate on X- axis is always 0

It is given that X-axis intersects the line connecting points P &Q, hence the value of y-coordinate of intersection point A will be 0.

∴ we can consider the coordinates of point A as (x, 0)

Next, let’s consider that the line PQ is divided in the ratio of m : n.

We know that, by section formula, if a point (x, y) divides the line joining the points (x1, y1​) and (x2​, y2​) in the ratio m : n, then the coordinates of intersection point (x, y) is given by:

(\frac{m x_2 + n x_1}{m + n}, \frac{m y_2 + n y_1}{m + n})

Here, it is given that

P (2, – 3) = (x1, y1​)

Q (5, 6) = (x2​, y2​),

Let’s consider line is divided in the ratio of m : n

Hence the y-coordinate of point A:

y = \frac{m (6) + n (- 3)}{(m + n)}

∴  0 = \frac{m (6) + n (- 3)}{(m + n)}

∴ 6 m – 3 n = 0 

∴ 6 m = 3 n

∴ 2 m = n

∴ m : n = 1 : 2

Therefore, the line is divided in the ratio of 1 : 2.

(ii) Coordinates of intersection point:

From the section formula, let’s find the value of x coordinate:

x = \frac{m x_2 + n x_1}{m + n}

∴ x = \frac{(1) (5) + (2)(2)}{2 + 1}

∴ x = \frac {9}{3} = 3

Since, value of y coordinate is 0 (being on X-axis)

Therefore the coordinates of intersection point A are (3, 0).

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