**Q) **If Q(0,1) is equidistant from P(5,-3) and R (x,6), find the values of x.

**Ans: **

since the Point Q is equidistant, then

Distance between P & Q = Distance between R & Q

(5-0)^{ 2} + (-3-1)^{ 2} = (x-0)^{2} + (6-1)^{2}

or 25 +16 = x^{2} + 25

or x^{2} = 16

**or x = 4, x = -4 **