Q) Evaluate (5/cot2 30°) + (1/ sin2 60°) – cot2 45° + 2 sin2 90° Ans: Givent that, – cot2 45 + 2 sin2 90 = + – (1)2 + 2 (1)2 = + – 1 + 2 = 3 – 1 + 2 = 4

Q) Evaluate (5/cot2 30°) + (1/ sin2 60°) - cot2 45° + 2 sin2 90° Ans: Givent that, $\frac{5}{\cot^2 30} + \frac{1}{\sin^2 60}$ - cot2 45 + 2 sin2 90 = $\frac{5}{(\sqrt3)^2}$ + $\frac{1}{(\frac{\sqrt3}{2})^2}$ - (1)2 + 2 (1)2 = $\frac{5}{3}$ + $\frac{4}{3}$ - 1 + 2 = 3 - 1 + 2 = 4