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Q) Evaluate (5/cot2 30°) + (1/ sin2 60°) – cot2 45° + 2 sin2 90°

Ans:

Givent that, \frac{5}{\cot^2 30} + \frac{1}{\sin^2 60} – cot2 45 + 2 sin2 90

= \frac{5}{(\sqrt3)^2} + \frac{1}{(\frac{\sqrt3}{2})^2} – (1)2 + 2 (1)2

= \frac{5}{3} + \frac{4}{3} – 1 + 2

= 3 – 1 + 2

= 4

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