**Q) A man has a Recurring Deposit Account in a bank for 3½ years. If the rate of interest is 12% per annum and the man gets Rs. 10,206 on maturity, find the value of monthly instalments.**

**Ans: **Given that:

RD tenure = 3.5 years = 42 months

Rate of Interest = 12% p.a.

Maturity amount = 10,206

**Step 1:** Let the Monthly instalment value be P

∴ Total investment = n x P = 42 x P = 42 P

**Step 2:** Next, we know that Interest Amount is given by:

I = P ×

= P x

= P x 21 x 43 x

= P

**Step 3:** We know that, Maturity value of RD account = Total investment + Interest Amount

∴ 10206 = 42 P + = P

∴ 10206 x 100 = 4200 P + 903 P

∴ 10206 x 100 = 5103 P

∴ P =

∴ P = 200

**Therefore, the Monthly Instalment value is Rs. 200**

**Check:** If Monthly Instalment value is 200, then money invested over 42 months = 42 x 200 = 8400

*Interest earned = P × *

*= 200 x **= 1806*

*Total maturity amount = 8400 + 1806 = 10206*

*Since this amount matches with given maturity amount, our answer is correct.*

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