**Q) A tent is in the shape of a right circular cylinder up to a height of 3 m and then a right circular cone, with a maximum height of 13.5 m above the ground. Calculate the cost of painting the inner side of the tent at the rate of 2 per square metre, if the radius of the base is 14 m.**

**Ans: **Let’s draw a diagram to better understand the question:

Here, in this question, it is given that:

Height of total shape = 13.5 m, height of cylindrical shape = 3 m,

Therefore, height of the canonical top = 13.5 – 3 = 10.5 m

Radius of the model = 14 m,

Therefore, slant height of the canonical top = = 17.5 m

Curved surface area of canonical top =

= (14)(17.5) = 770 m^{2 }…….. (i)

Curved surface area of cylindrical base = 2

= 2 x (14)(3) = 264 m^{2 }……….. (ii)

Therefore, Curved surface Area of tent = 770 + 264 = 1034 m^{2}

Since the cost of painting = Rs. 2 / m^{2}

Now, the cost of painting the surface area = 1034 x 2 = 2068

**Therefore cost of painting the inner surface area is Rs. 2,068.**

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