Q) A circle is touching the side BC of a Δ ABC at the point P and touching AB and AC produced at points Q and R respectively. Prove that AQ = 1 (Perimeter of Δ ABC) Ans: Perimeter of the triangle Δ ABC, P = AB + AC + BC ∴ P = AB […]
A circle is touching the side BC of a A ABC at the point P and touching AB Read More »
