Q) Evaluate: (2𝑠𝑖𝑛 2 600 − 𝑡𝑎𝑛 2 300) / 𝑠𝑒𝑐2 450

We know that: sin 600 = $\frac{\sqrt 3}{2}$; tan 300 = $\frac{1}{\sqrt 3}$; sec 450 = $\sqrt 2$ By submitting these values in the given expression, we get: $ \frac{2 \sin^2 60 - \tan ^2 30}{\sec ^2 45}$ = $ \frac{2 (\frac{\sqrt 3}{2})^2 - (\frac{1}{\sqrt 3})^2}{(\sqrt 2)^2}$ = $ \frac{2 (\frac{3}{4}) - (\frac{1}{3})}{(2)}$ = $ \frac{(\frac{3}{2}) - (\frac{1}{3})}{(2)}$ = $ \frac{(\frac{7}{6})}{(2)}$ = $\frac{7}{12}$ Please do press “Heart” button if you liked the solution.