Q) Find the area of the sector of a circle of radius 42 cm and of central angle 30 deg. Also, find the area of the corresponding major sector. [Use π = 22/7]

(Q 30 – 30/2/1 – CBSE 2026 Question Paper)

Ans: 

Step 1: Let’s make a diagram for our better understanding:

Here, Radius is 42 cm, ∠ AOB at center = 30

Step 2: Area of Sector OAPB =

=

=

=

= 22 x 21 = 462 cm ²

Therefore, the area of minor sector is 462 cm ².

Step 3: Now Area of the major sector, OAQB

= Area of the circle – Area of the minor sector, OAPB

= π (42) ² – 462

= (42) ² – 462

= 5544 – 462 = 5082 cm ²

Therefore, the area of major sector is 5082 cm ².

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