**Q) Find the ratio in which the point (- 1, k) divides the line segment joining the points (- 3, 10) and (6, – 8). Also, find the value of k.**

**Ans: **

**Step 1: Finding the division ratio:**

Now, by section formula, coordinates of point P (X, Y) which lies between two points (x_{1}, y_{1}), (x_{2}, y_{2}) will be given by:

P (X,Y) =

here, point divides the line in ratio of m_{1 :} m_{2 }

Let’s consider the point C(-1, k) divides the line AB in ratio of P : 1 and points given are (- 3, 10) and (6, – 8).

By transferring values in the above section formula, we get:

For x coordinate:

∴ – 1 =

∴ (- 1) (P + 1) = 6 P – 3

∴ – P – 1 = 6 P – 3

∴ 7 P = 3 – 1 = 2

∴ P =

∴ P : 1 = 7 : 2

**Therefore, the point C divides the line AB in ratio of 7:2.**

**Step 2: Finding value of k:**

Let’s find value of y coordinate from section formula:

y =

∴ k =

∴ k (P + 1) = 10 – 8 P

By substituting value of P = , we get:

k ( + 1) = 10 – 8 x

∴ k () = 10 – 28 = – 18

∴ k = – 18 x = – 4

**Therefore, value of y is – 4.**

*Please press the heart button, if you liked the solution.*