**Q) **How many terms are there in an A.P. whose first and fifth terms are -14 and 2, respectively and the last term is 62.

**Ans: **Let’s consider an A.P with first term as N1 and common difference as ‘d’.

Next, we know that n^{th} term of an A.P. = a + (n-1) d

here, a = first term,

n = total no. of terms till n^{th} term

d = common difference between any two terms

Therefore, 1^{st} term, N_{1} = a = -14 (given)

and 5^{th} term, N_{5 }= -14 + 4d = 2 (given)

d = 4

Now we are given that 62 is the last term.

if 62 is the n^{th} term, then:

62 = -14 + (n-1) 4

**n = 20**

**Therefore, there are 20 terms in the given A.P.**