Q) The ratio of the 11th term to 17th term of an A.P. is 3:4. Find the ratio of 5th term to 21st term of the same A.P. Also, find the ratio of the sum of first 5 terms to that of first 21 terms.
Ans:
VIDEO SOLUTION
STEP BY STEP SOLUTION
We know that nth term of an A.P. = a + (n-1) d
Therefore, 11th term, N11 = a + 10d and 17th term, N17 = a + 16d
Given that : =
=
or 4a + 40 d = 3a + 48 d
or a = 8d ……………………………………. equation no. (i)
Now 5th term N5 = a + 4d and 21st term N21 = a + 20 d
Therefore, =
Substituting a = 8d from equation (i), we get
= =
Therefore, N5:N21 = 3:7
Let’s calculate ratio of the sum of first 5 terms to that of first 21 terms.
We know that sum of n terms of an A.P. Sn = (2a + (n-1) d)
Sum of first 5 terms, S5 = (2a + 4d)
and Sum of first 21 terms, S21 = (2a + 20d)
Therefore, =
=
Substituting a = 8d from equation (i), we get
=
=
=
Therefore, S5 : S21 = 25 : 189