Q) Which term of the A.P. : 65, 61, 57, 53,………… is the first negative term.

Ans: This is A.P. of decreasing order. In the given A.P., we can see that:

First term a = 65 and common difference d = -4

Let first negative term be nth term, say Tn

We know that nth term of an A.P. is given by Tn =  a + (n-1) d

Since it has to be first negative term, therefore:

a + (n-1) d < 0

\therefore   65 + (n-1) (-4) < 0

69 – 4n < 0

69 < 4n

n > \frac{69}{4} = 17.25

Since term count has to be integer, hence, nearest integer value which is greater than 17.25 is 18.

Therefore, 18th term of the given A.P. will be its first negative term.

Check:

Value of 17th term will be, N17 = 65 + (17 – 1) (- 4) = 65 – 64 = 1

and value of 18th term will be, N18 = 65 + (18 – 1) (- 4) = 65 – 68 = – 3, which will be the first negative term after 1.

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