Q) If α, β are the zeroes of the polynomial p(x) = x^2 − 3x − 1, then find the value of 1/α +1/β.
(Q21 – 30/1/1 – CBSE 2026 Question Paper)
Ans:
Step 1: Given polynomial, p (x) = x 2 – 3 x – 1
For p (x) = 0, x 2 – 3 x – 1 = 0
Let’s compare the given polynomial with standard quadratic polynomial:
a x 2 + b x + c
here, we get, a = 1, b = – 3 and c = – 1
Step 2: Next, we know that if α and β are zeroes of quadratic polynomial, then
Sum of the zeroes, α + β =
= 3
and Product of zeroes, α . β =
= – 1
Step 3: ∵ We need to find value of ![]()
Let’s simplify it:
![]()
Step 4: Now we substitute the value of (α + β) and α . β from step 2
∴ ![]()
=
= – 3
Therefore, the value of
is – 3.
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