Q) If 4 cot2 45° – sec2 60° + sin2 60° + p = 
then find the value of p.
Ans:
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4 cot2 45° – sec2 60° + sin2 60° + p =
4 (1)2 – (2)2 + 
4 – 4 + + p =
p = 0
Therefore, the value of p is 0
Q) If 4 cot2 45° – sec2 60° + sin2 60° + p = then find the value of p.
Ans:
4 cot2 45° – sec2 60° + sin2 60° + p =
4 (1)2 – (2)2 +
4 – 4 + + p =
p = 0
Therefore, the value of p is 0