πŸš€ Download 21 Must‑Solve Questions for Class 10 Boards!
// Add custom schema markup to homepage function saplingacademy_homepage_schema() { if ( is_front_page() ) { // Only output on homepage } } add_action('wp_head', 'saplingacademy_homepage_schema');

Q) If AP and DQ are medians of triangles ABC and DEF respectively, where βˆ†ABC~ βˆ†DEF, then prove that 𝐴𝐡/𝐷𝐸 = 𝐴𝑃/𝐷𝑄.

[Q 23 – Sample Question Paper – CBSE Board 2026]

Ans:Β 

If AD and PM are medians Triangles CBSE 10th important questions

Step 1: Given that,Β  Ξ” ABC ~ Ξ” DEF, therefore

∠ B = ∠ EΒ  Β …………. (i)

and \frac{AB}{DE} = \frac{BC}{EF} …………. (ii)

Step 2: Since AP is median of BC, hence BC = 2 BP

Similarly, DQ is median of EF, hence EF = 2 EQ

Let’s substitute these 2 values in equation (ii), we get:

\frac{AB}{DE} = \frac{BC}{EF} = \frac{2BP}{2EQ}

∴ \frac{AB}{DE} = \frac{BP}{EQ} …….. (iii)

Step 3: Let’s compare Ξ” ABP ~and Ξ” DEQ

Here, \frac{AB}{DE} = \frac{BP}{EQ}Β  Β  (already proven in step 2)

∠ B = ∠ Q                      (identified in step 1)

∴ Ξ” ABP ~ Ξ” DEQΒ  Β  Β  Β  Β (by SAS similarity)

Therefore, \frac{AB}{DE} = \frac{AP}{DQ}

Hence proved.

Please press the β€œHeart” button if you like the solution.

Leave a Comment

Your email address will not be published. Required fields are marked *

Scroll to Top