Q) In a class test, Veer scored 6 more than twice as many marks as Kevin scored. If one of them had scored 4 more marks, their total score would have been 40. Find the marks obtained by Veer and Kevin.

(Q 28 A – 30/4/2 – CBSE 2026 Question Paper)

Ans:

Let’s consider the marks obtained by Veer = X and marks scored by Kevin = Y

Step 1: By 1st condition, “Veer scored 6 more than twice as many marks as Kevin scored”

∴ X = 6 + 2 Y

∴ X – 2 Y = 6 ………. (i)

Step 2: By 2nd condition, “If one of them had scored 4 more marks, their total score would have been 40”

∴ X + Y + 4 = 40

∴ X + Y = 40 – 4

∴ X + Y = 36 ……… (ii)

Step 3: By subtracting equation (i) from equation (ii), we get:

(X + Y) – (X – 2 Y) = 36 – 6

∴ X + Y – X + 2 Y = 36 – 6

∴ 3 Y = 30

∴ Y = 10

Step 4: From equation (ii), we have: X + Y = 36

By substituting value of Y in it, we get:

∴ X + 10 = 36

∴ X = 36 – 10 = 26

Therefore, the marks obtained by Veer and Kevin are 26 and 10 respectively.

Check: Let’s check given conditions for X = 26 and Y = 10
1st condition: X = 2 Y + 6 = 2 x 10 + 6 = 26 ……… it is matched
2nd condition: X + Y + 4 = 26 + 10 + 4 = 40 ……. it is matched.
Since both the given conditions are matched, our solution is correct.

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