Q)Jaya scored 40 marks in a test getting 3 marks for each correct answer and losing 1 mark for each incorrect answer., Had 4 marks being awarded for each correct answer and 2 marks were deducted for each incorrect answer then Jaya again would have scored 40 marks. How many questions were there in the Test?

Ans: 

Step 1: Let X be the number of questions which are answered correctly

and Y be the number of questions which are answered incorrectly.

Therefore, total no. of questions in the test = X + Y

Step 2:  Let’s take 1st case: Jaya gets 40 marks with 3 marks for correct answer and – 1 for incorrect answer.

∵ Marks for 1 correct answer = 3

∴ Marks for X correct answers = 3 (X) = 3 X

Similarly, marks for 1 incorrect answer = – 1

∴ Marks for Y incorrect answer = – 1 (Y) = – Y

Therefore, Jaya’s total marks = Marks for correct answers + Marks for incorrect answers

∴ 40 = 3 X – Y …….. (i)

Step 3:  Let’s take 1st case: Jaya gets 40 marks with 4 marks for correct answer and – 2 for incorrect answer.

∵ Marks for 1 correct answer = 4

∴ Marks for X correct answers = 4 (X) = 4 X

Similarly, marks for 1 incorrect answer = – 2

∴ Marks for Y incorrect answer = – 2 (Y) = – 2 Y

Therefore, Jaya’s total marks = Marks for correct answers + Marks for incorrect answers

∴ 40 = 4 X – 2 Y …….. (ii)

Step 4: Let’s solve equations (i) and (ii) and find the values of X and Y.

To solve these we multiply equation (i) by 2 and subtract equation (ii) from it, we get:

(2 x 40) – (40) = 2 (3 X – Y) – (4 X – 2 Y)

80 – 40 = 6 X – 2 Y – 4 X + 2 Y

40 = 2 X

X = \frac{40}{2} = 20

By substituting value of X = 20 in equation (i), we get:

40 = 3 X – Y

∴ 40 = 3 (20) – Y

∴ 40 = 60 – Y

∴ Y = 60 – 40 = 20

Step 5: Now we have values of X and Y,

∴ Total number of questions = X + Y

= 20 + 20 = 40

Therefore, total no. of questions in the test are 40. 

Check: let’s put X = 20 and Y = 20 in, equation (i), we get: 3 (20) – (20) = 60 – 20 = 40 … This matches with the given condition. hence values of X and Y are correct. 

Similarly, from equation (ii), we get: 4(20) – 2(20) = 80 – 40 = 40… This also matches with the given condition. hence values of X and Y are correct. 

Since both conditions are satisfied, hence our answer is correct.

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