Q) The perimeter of sector OAB of a circle with centre O and radius 5.6 cm, is 15.6 cm. Find length of the arc AB. Also find the value of θ.

(Q 31 – 30/4/2 – CBSE 2026 Question Paper)
Ans:
Length of Arc AB:
We are given: Perimeter of sector OAB = 15.6 cm
Length of radius OA & OB = 5.6 cm
∵ The perimeter of sector OAB is given by = length of Arc AB + OA + OB
∴ 15.6 = Arc AB + 2 (5.6)
∴ Arc AB = 15.6 – 11.2 = 4.4
Therefore, length of Arc AB is 4.4 cm
Value of θ:
Since length of Arc is given by: 2 π r ![]()
Here, length of arc AB = 4.4 cm (calculated above) 
Radius r = 5.6 cm
∴ for length of the arc AB:
2
(5.6)
= 4.4
∴ 44 (0.8)
= 4.4
∴
= ![]()
∴
= ![]()
∴ θ =
= 45 0
Therefore, the value of θ is 45 0
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