**Q) **Two water taps together can fill a tank in 9 hours. The tap of larger diameter takes 10 hours less than the smaller one to fill the tank separately. Find the time in which each tap can separately fill the tank.

**Ans: **It is given that,

Time taken by both water taps together = 9 hrs

We need to find out: Time to fill the tank by each pipe individually

Let’s consider smaller diameter pipe fills the tank in X hrs and Volume of the tank is V.

In the question, it is given that time taken by larger diameter pipe is 10 hrs less than smaller diameter pipe

Therefore, hence, time taken by larger diameter pipe is = X – 10 hrs

Since smaller diameter pipe fills the tank of volume V in X hrs

Hence, the volume filled by smaller diameter pipe in 1 hr =

Similarly, larger diameter pipe fills the tank of volume V in Y hrs

Hence, the volume filled by larger diameter pipe in 1 hr =

Therefore, the volume filled by both pipes together in 1 hr =

=

Now, volume of tank is filled by both pipes in 1 hr

Therefore, Volume V of the tank will be filled by both pipes in:

= =

Its given that the both pipes fill the tank in hrs

8 X (X – 10) = 75 (2X – 10)

8 X^{2} – 80 X = 150 X – 750

8 X^{2} -230 X + 750 = 0

8 X^{2} -200 X – 30 X + 750 = 0

8X(X – 25) -30 (X – 25) = 0

X = 25 hrs and

X = = hrs

These are the 2 values of the time taken by smaller diameter pipe

Since, time taken by larger diameter pipe is 10 hrs less than smallerdiameter pipe,

hence values for time taken by this pipe will be:

25 – 10 = 15 hrs

and – 10 = hrs

Since value of time taken can not be negative, X

**Hence, time taken by smaller diameter pipe is 25 hrs ****and time taken by larger diameter pipe is 15 hrs.**