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Q) A(3, 0), B(6, 4) and C(-1, 3) are vertices of a triangle ABC. Find length of its median BE.

Ans: Let’s plot the points on the graph:

A(3, 0), B(6, 4) and C(-1,

Step 1:  To draw median BE, point E lies on AC

Let’s consider the coordinates of E are (x, y)

Since E is the midpoint of A C, we will find out the coordinates of E.

We know that the coordinates of mid point of 2 coordinates (X1, Y1) and (X2, Y2) given by:

(X, Y) = A(3, 0), B(6, 4) and C(-1,

∴ value of coordinates of midpoint E of A (3, 0) and C(- 1, 3) are:

(X, Y) = A(3, 0), B(6, 4) and C(-1,

= A(3, 0), B(6, 4) and C(-1,

Step 2: Next, we find out the length of line BE, where B is (6, 4) and E is (1, A(3, 0), B(6, 4) and C(-1,)

We know that the distance between two points (X1, Y1) and (X2, Y2) is given by:

S = [(X2 – X1)2 + (Y2 – Y1)2 ]

∴  BE = A(3, 0), B(6, 4) and C(-1,

= A(3, 0), B(6, 4) and C(-1,

= A(3, 0), B(6, 4) and C(-1, units

Therefore, the length of the median BE is A(3, 0), B(6, 4) and C(-1, units.

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