Q) A straight highway leads to the foot of a tower. A man standing on the top of the 75 m high tower observes two cars at angles of depression of 30Β° and 60Β°, which are approaching the foot of the tower. If one car is exactly behind the other on the same side of the tower, find the distance between the two cars. (Use β3 = 1.73)
Ans:

Let’s consider AB be the tower and 2 cars are at points C & D.
In Ξ ABC,
tan 600 =Β Β ![]()
β3 = ![]()
AC = 25 β3
In Ξ ABD,
tan 300 =Β Β ![]()
![]()
d + 25β3 = 75 β3
d = 50 β3 = 50 x 1.73 = 86.5
Therefore, the distance between the two cars is 86.5 m
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