**Q) ****A pole 6m high is fixed on the top of a tower. The angle of elevation of the top of the pole observed from a point P on the ground is 60 and the angle of depression of the point P from the top of the tower is 45. Find the height of the tower and the distance of point P from the foot of the tower. (use = 1.73)**

**A****ns:**

**Step 1: Diagram for this question: **

Let AB be the tower of H height and AC be the pole of 6 m on top of tower.

The distance between the Point P and the tower be D and angle of elevations be as shown in the image above.

**Step 2: Calculating height H and distance D :**

In Δ ABP, tan 45 =

∴ D = H …. (i)

**Step 3: Find the height H:**

Now in Δ CBP, tan 60 =

…. (ii)

By substituting value of D from equation (i) in equation (ii), we get:

= 3 (1.73 + 1) = 3 (2.73) = 8.19 m

**Therefore, the height of the tower is 8.19 m**

**Step 4: Find the distance D:**

from equation (i), we get the distance D = H = 8.19 m

**Therefore, the distance of the point P from the tower is 8.19 m****.**

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