**Q) ****The sum of first and eighth terms of an A.P. is 32 and their product is 60. Find the first term and common difference of the A.P. Hence, also find the sum of its first 20 terms.**

**Ans: **Let’s consider the first terms of AP is a and the common difference is d.

**(i).** **Calculating first term & Common difference:**

Since n^{th} terms of an AP is given by,

∴ 8^{th} term, = a + (8 – 1) d = a + 7 d

Since it is given that the sum of first term & 8^{th }terms is 32,

∴ a + (a + 7 d) = 32

∴ a + 7 d = 32 – a….. (i)

Also, it is given that the product of first term & 8^{th }terms is 60,

∴ a (a + 7 d) = 60 ….. (ii)

By solving equation (i) and equation (ii), we get:

a [32 – a)] = 60

∴ 32 a – a ^{2 }= 60

∴ a ^{2} – 32 a + 60 = 0

∴ a ^{2} – 30 a – 2 a + 60 = 0

∴ (a – 30) (a – 2) = 0

Therefore, a = 30 or a = 2

By substituting value of a = 30 in equation (i), we get:

a + 7 d = 32 – a

∴ 7 d = 32 – 2 a

∴ 7 d = 32 – 2 (30) = 32 – 60 = – 28

∴ d = – 4

By substituting value of a = 2 in equation (i), we get:

a + 7 d = 32 – a

∴ 7 d = 32 – 2 a

∴ 7 d = 32 – 2 (2) = 32 – 4 = 28

∴ d = 4

**Therefore, for first term a = 30, the common difference, d is – 4 and for first term, a = 2, the common difference, d is 4.**

**(ii). Calculating sum of 20 terms:**

We know that the sum of n terms of an AP is given by,

a) Here, n = 20, a = 30, d = – 4

= 10 (60 – 76) **= – 160**

b) Here, n = 20, a = 2, d = 4

= 10 (4 + 76) **= 800**

**Therefore, for first term a = 30, the sum of 20 terms is – 160 and for first term, a = 2, the sum of 20 terms is 800.**

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