Q) Governing council of a local public development authority of Dehradun decided to build an adventurous playground on the top of a hill, which will have adequate space for parking.

After survey, it was decided to build rectangular playground, with a semi-circular area allotted for parking at one end of the playground. The length and breadth of the rectangular playground are 14 units and
7 units, respectively. There are two quadrants of radius 2 units on one side for special seats.
Based on the above information, answer the following questions :
(i) What is the total perimeter of the parking area?
(ii) (a) What is the total area of parking and the two quadrants?
Ā Ā Ā OR
(b) What is the ratio of area of playground to the area of parking area?
(iii) Find the cost of fencing the playground and parking area at the rate of Rs. 2 per unit.
Ans:Ā
VIDEO SOLUTION
STEP BY STEP SOLUTION
(i) Perimeter of parking area = outer perimeter of semicircle + diagonal of semicircle
= ![]()
Given that, breadth or diameter of semicircle = 7 units
hence, ![]()
Therefore, Perimeter of parking area = ![]()
= 18 units
(ii)(a) Area of parking space and two quadrants = Area of Parking Space + Area of 2 quadrants
Since, both these type of areas have different radius, let’s consider that
is the radius of parking space and
is the radius of quadrant. We know that:
Since
(calculated above)
and
(given)
Area of parking space and two quadrants = ![]()
Total Area = ![]()
=
Ā = ![]()
= 25.54 sq. unitsĀ
(ii) (b) Ratio of Playground area to Parking area = ![]()
=
Ā = ![]()
= 56:11
(iii) Perimeter of required fencing = perimeter of playground + perimeter of parking area
= 2 (l + b) + ![]()
= 2(14+7) +
x ![]()
= 42 + 11 = 53 units
Cost of fencing @ Rs. 2 per unit = 53 x 2
= Rs. 106
This completes all the required solutions.
