**Q) A solid iron pole consists of a solid cylinder of height 200 cm and base diameter 28 cm, which is surmounted by another cylinder of height 50 cm and radius 7 cm. Find the mass of the pole, given that 1 cm3 of iron has approximately 8 g mass.**

**Ans:**

For better understanding, let’s draw a diagram for the given question:

We are given the following:

Height of large cylinder, H_{L} = 200 cm

Diameter of large cylinder, D_{L} = 28 cm

∴ Radius of large cylinder, R_{L} = = 14 cm

Height of small cylinder, H_{S} = 50 cm

Radius of small cylinder, R_{S} = 7 cm

Volume of the Pole = Volume of large cylinder + volume of small Cylinder

= π R_{L}^{2} H_{L} + π R_{S}^{2} H_{S}

= π (14)^{2} (200) + π (7)^{2}(50)

= 39200 π + 2450 π

= 41650 π

= 41650 x = 5950 x 22 = 130900 cm^{3}

Since, it is given that mass of 1 cm^{3} of iron = 8 gm

∴ mass of 130900 cm^{3} of iron = 8 x 130900 gm

= = 1047.2 Kg

**Therefore, the mass of the iron pole is 1047.2 Kg**

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