**Q) **A tent is in the shape of a cylinder surmounted by a conical top. If the height and radius of the cylindrical part are 3 m and 14 m respectively, and the total height of the tent is 13.5 m, find the area of the canvas required for making the tent, keeping a provision of 26 m² of canvas for stitching and wastage. Also, find the cost of the canvas to be purchased at the rate of 500 per m².

**Ans:**

Here, in this question, it is given that:

Height of total shape = 13.5 m, height of cylindrical shape = 3 m,

Therefore, height of the canonical top = 13.5 – 3 = 10.5 m

Radius of the model = 14 m,

Therefore, slant height of the canonical top = = 17.5 m

Curved surface area of canonical top =

= (14)(17.5) = 770 m^{2 }…….. (i)

Curved surface area of cylindrical base = 2

= 2 x (14)(3) = 264 m^{2 }……….. (ii)

Therefore, Curved surface Area of tent = 770 + 264 = 1034 m^{2}

It is given that a provision of 26 m^{2 }is required, Therefore, Area of the canvas required to make this tent = 1034 + 26 **= 1060 m ^{2 }**

Since the cost of canvas = Rs. 500 / m^{2}

Therefore, the cost of the canvas = 1060 x 500 =** Rs. 530,000**