Q) 22. Find the type of triangle ABC formed whose vertices are A(1, 0), B(-5, 0) and C(-2, 5).

Ans: Step 1: Let’s plot the points on the graph:

Step 2:  Given vertices are A(1, 0), B(- 5, 0) and C(- 2, 5).

Let’s find out lengths of all the sides:

We know that the distance between two points (X₁, Y₁) and (X₂, Y₂) is given by:

S = √ [(X₂ – X₁)² + (Y₂ – Y₁)² ]

∴  AB =

∴  BC =

∴  AC =

Step 3:

Since the two sides BC and AC are same, hence Δ ABC is an isosceles triangle.

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