**Q) 22. Find the type of triangle ABC formed whose vertices are A(1, 0), B(-5, 0) and C(-2, 5).**

**Ans: Step 1: **Let’s plot the points on the graph:

**Step 2: **Given vertices are A(1, 0), B(- 5, 0) and C(- 2, 5).

Let’s find out lengths of all the sides:

We know that the distance between two points (X_{1}, Y_{1}) and (X_{2}, Y_{2}) is given by:

S = **√ **[(X_{2} – X_{1})^{2 } + (Y_{2} – Y_{1})^{2 }]

∴ AB =

∴ BC =

∴ AC =

**Step 3: **

**Since the two sides BC and AC are same, hence Δ ABC is an isosceles triangle.**

**Please press the “Heart”, if you liked the solution.**